There is a very small amount of red shift. If you were standing on the equator watching a sunset, then your radial velocity relative to the sun is only ~461m/s. So the green light from the sun 550nm would be red shifted by +0.0008nm. That little red shift wouldn’t be noticeable. However, as the sun sets there’s a lot more atmosphere in the way, which scatters blue light more than red light (Why the sky is blue). Also in a sunrise you are moving towards the sun, so sunrises would be blue! :P
There is a very small amount of red shift. If you were standing on the equator watching a sunset, then your radial velocity relative to the sun is only ~461m/s. So the green light from the sun 550nm would be red shifted by +0.0008nm. That little red shift wouldn’t be noticeable. However, as the sun sets there’s a lot more atmosphere in the way, which scatters blue light more than red light (Why the sky is blue). Also in a sunrise you are moving towards the sun, so sunrises would be blue! :P
Are you sure those numbers are right? The proportions of 550nm/0.08nm and c/461m/s are very different.
Oops you’re right missed a few zeros.